The IUPAC name for the following compound is $ \mathrm{BrCH}_{2} \mathrm{CH}_{2}…
The IUPAC name for the following compound is
$
\mathrm{BrCH}_{2} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{COCH}_{3}
$
1-bromohept-3-en-6-one
2-oxo-bromohept-4-one
7-bromo-2-oxohept-4-one
7-bromohept-4-en-2-one
Solution
Carbonyl group has more priority than double bond and bromine, so numbering should be start from carbonyl side.
$
\mathrm{Br}_{7} - \mathrm{C}_{6} \mathrm{H}_2 - \mathrm{C}_{5} \mathrm{H}_2 - \mathrm{C}_{4} \mathrm{H} = \mathrm{C}_{3} \mathrm{H} - \mathrm{C}_{2} \mathrm{H}_2 \mathrm{C} \mathrm{O} - \mathrm{C}_{1} \mathrm{H}_3
$
Thus, the correct IUPAC name of the given compound is 7-bromohept-4-en-2-one.
Hence, the correct option is (4)