The ionization constant of ammonium hydroxide is $1.77 \times 10^{-5}$ at $298 \mathrm{~K}$. Hydrolysis…

The ionization constant of ammonium hydroxide is $1.77 \times 10^{-5}$ at $298 \mathrm{~K}$. Hydrolysis constant of ammonium chloride -
  1. $5.65 \times 10^{-12}$
  2. $5.65 \times 10^{-10}$
  3. $6.50 \times 10^{-12}$
  4. $5.65 \times 10^{-13}$

Solution

$\mathrm{K}_{\mathrm{h}}=\frac{\mathrm{K}_{\mathrm{W}}}{\mathrm{K}_{\mathrm{b}}}=\frac{10^{-14}}{1.77 \times 10^{-5}}=5.65 \times 10^{-10}$

Asked in: NEET 2009 (Mains)

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