The ionic radii ( in Å ) of N 3 - , O 2 - and F - are respectively:

The ionic radii (in  Å) of N3-, O2-  and  F-  are respectively:
  1. 1.71, 1.36 and 1.40
  2. 1.36, 1.40 and 1.71
  3. 1.36, 1.71 and 1.40
  4. 1.71, 1.40 and 1.36

Solution

As Z e ionic radius decreases for isoelectronic species.

Z=number of protonse=number of electrons

N 3 - Z e = 7 1 0

O 2 - Z e = 8 1 0

F - Z e = 9 1 0

Trend of ionic radius: N 3 - > O 2 - > F -

Asked in: JEE Main 2015 (04 Apr)

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