The ion with smallest radius among the following is

The ion with smallest radius among the following is
  1. $\mathrm{Ca}^{2+}$
  2. $\mathrm{K}^{+}$
  3. $\mathrm{Ti}^{4+}$
  4. $\mathrm{Sc}^{3+}$

Solution

All the given species have the elements belonging to the same period and ionic radii decrease in a period from left to right. $\mathrm{Ti}^{4+}$ lies to the right of the other species and would be even more small due to a greater positive charge. Thus, order of radii would be :- $` \mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Sc}^{3+}>\mathrm{Ti}^{4+} $

Asked in: AP EAMCET 2023 (18 May Shift 2)

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