The inverse point of $(1,3)$ with respect to the circle $x^2+y^2-4 x-6 y+9=0$ is

The inverse point of $(1,3)$ with respect to the circle $x^2+y^2-4 x-6 y+9=0$ is
  1. $(2,3)$
  2. $(2,-3)$
  3. $(-2,3)$
  4. $(-2,-3)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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