The internal resistance of a $2.1 \mathrm{~V}$ cell which gives a current of $0.2 \mathrm{~A}$ through a resistance of $10 \Omega$ is

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Aicharya · Accepted Answer

$\begin{aligned} & I=\frac{E}{R+r} \ & 0.2 \times(10+r)=2.1 \ & 10+r=\frac{2.1}{2} \times 10 \ & r=10.5-10=0.5 \Omega\end{aligned}$

The internal resistance of a $2.1 \mathrm{~V}$ cell which gives a current of $0.2 \mathrm{~A}$ through a…