The integrating factor of the differential equation $\frac{d y}{d x}(x \log x)+y=4 \log x$ is

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Aicharya · Accepted Answer

We have $\frac{d y}{d x}(x \log x)+y \quad=4 \log x$ $	herefore \frac{d y}{d x}+\left(\frac{1}{x \log x}ight) y=\frac{4}{x}$ $	herefore$ I.F. $=e^{\int \frac{d x}{x \log x}}=e^{\log (\log x)}=\log x$

The integrating factor of the differential equation $\frac{d y}{d x}(x \log x)+y=4 \log x$ is

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