The integral ∫ d x ( x + 4 ) 8 7 ( x - 3 ) 6 7 is equal to: (where C is a constant of integration)

1. ${\left(\frac{x-3}{x+4}\right)}^{\frac{1}{7}}+C$
2. ${\left(\frac{x-3}{x+4}\right)}^{\frac{-1}{7}}+C$
3. $\frac{1}{2}{\left(\frac{x-3}{x+4}\right)}^{\frac{3}{7}}+C$
4. $-\frac{1}{13}{\left(\frac{x-3}{x+4}\right)}^{\frac{-13}{7}}+C$

Solution

Asked in: JEE Main 2020 (09 Jan Shift 1)

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