The integral ∫ c o s lnx d x , is equal to

The integral coslnxdx, is equal to 
  1. x2coslnx-sinlnx+C
  2. xcoslnx-sinlnx+C
  3. xcoslnx+sinlnx+C
  4. x2coslnx+sinlnx+C

Solution

Given, I=coslnxdx

Let, lnx=tx=etdx=etdt

I=etcostdt

etcostdt=12etcost+sint+cost-sintdt

etcost dt=12etcost+sint+C, where C is the constant of integration.

=x2coslnx+sinlnx+C
 

Asked in: JEE Main 2019 (12 Jan Shift 1)

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