The integral ∫ 2 x 3 - 1 x 4 + x d x , is equal to

1. $\frac{1}{2}{\mathrm{l}\mathrm{o}\mathrm{g}}_e\frac{{(x^3+1)}^2}{\left|x^3\right|}+C$
2. ${\mathrm{l}\mathrm{o}\mathrm{g}}_e\frac{|x^3+1|}{x^2}+C$
3. ${\mathrm{l}\mathrm{o}\mathrm{g}}_e\left|\frac{\left(x^3+1\right)}{x}\right|+C$
4. $\frac{1}{2}{\mathrm{l}\mathrm{o}\mathrm{g}}_e\frac{|x^3+1|}{x^2}+C$

Solution

Asked in: JEE Main 2019 (12 Apr Shift 1)

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