The integral ∫ ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a constant of integration)

Question

The integral &#8747; ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a constant of integration)

Aicharya · Accepted Answer

&#8747; ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 ( 2 x - 1 ) 2 + 5 d x ( 2 x - 1 ) 2 + 5 = t 2 2 2 x - 1 &#160; 2 d x = 2 &#160; t d t 2 t 2 - 5 d x = t d t So &#8747; t 2 - 5 cos t 2 t 2 - 5 d t = 1 2 sin t + c = 1 2 sin ( 2 x - 1 ) 2 + 5 + c

The integral ∫ ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a…

Solution

The integral &#8747; ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a…

Solution

The integral ∫ ( 2 x - 1 ) cos ( 2 x - 1 ) 2 + 5 4 x 2 - 4 x + 6 d x is equal to (where c is a…