The integral ∫ 1 + 2 cot x cosec x + cot x d x ,   0 < x < π 2   is equal to

The integral 1+2cotxcosecx+cotxdx, 0<x<π2 is equal to
  1. 2logsinx2+c
  2. 4logsinx2+c
  3. 4logcosx2+c
  4. 2logcosx2+c

Solution

Let I=1+2cotxcosec x+cotxdx  

I=2cotxcosecx+cosec2x+cot2xdx

I=cosec x+cot x2dx

I=cosec x+cot xdx

I=cosec x+cotxdx

I=logtanx2+logsinx+c, where c is the constant of integration.
I=logsinx2cosx2·2sinx2cosx2+c
I=2logsinx2+c

Asked in: JEE Main 2017 (08 Apr Online)

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