The instantaneous velocity of a particle moving in a straight line is given as v = α t + β t 2 ,…

The instantaneous velocity of a particle moving in a straight line is given as v=αt+βt2, where α and β are constants. The distance travelled by the particle between 1 s and 2 s is:
  1. 3α+7β
  2. 32α+73β
  3. α2+β3
  4. 32α+72β

Solution

V=αt+βt2

dsdt=αt+βt2

S1S2 ds=12αt+βt2dt

S2-S1=αt22+βt3312

As the particle is not changing direction So distance = displacement. Distance =α[4-1]2+β[8-1]3

=3α2+7β3

Asked in: JEE Main 2021 (25 Jul Shift 2)

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