The input signal given to C.E. amplifier having a voltage gain of 126 is $V_i=2 \cos \left(12…

The input signal given to C.E. amplifier having a voltage gain of 126 is $V_i=2 \cos \left(12 t+\frac{\pi}{3}\right)$. The corresponding output signal will be
  1. $252 \cos \left(12 \mathrm{t}+\frac{4 \pi}{3}\right)$
  2. $252 \cos \left(12 t+\frac{\pi}{3}\right)$
  3. $\quad 63 \cos \left(12 t+\frac{2 \pi}{3}\right)$
  4. $2 \cos \left(12 t+\frac{5 \pi}{3}\right)$

Solution

$\begin{aligned} & V_i=2 \cos \left(12 t+\frac{\pi}{3}\right) ...(given)\\ & \text { Voltage gain }=\frac{V_0}{V_i} \\ & V_0=126 \times 2 \cos \left(12 t+\frac{\pi}{3}\right) \\ & \quad=252 \cos \left(12 t+\frac{\pi}{3}\right) \end{aligned}$
In CE amplifier, $\mathrm{V}_0$ and $\mathrm{V}_{\mathrm{i}}$ have a phase difference of $\pi$ between them. $\begin{aligned} V_0 & =252 \cos \left(12 t+\frac{\pi}{3}+\pi\right) \\ & =252 \cos \left(12 t+\frac{4 \pi}{3}\right) \end{aligned}$ .

Asked in: MHT CET 2024 (16 May Shift 1)

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