The initial rates of decrease of $\mathrm{I}_2$ in acetone - iodine reaction catalysed by $\mathrm{H}^{+}$…

The initial rates of decrease of $\mathrm{I}_2$ in acetone - iodine reaction catalysed by $\mathrm{H}^{+}$ are given in the table. $\begin{array}{|c|c|c|c|c|} \hline \begin{array}{c} \text { Experiment } \\ \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{I}_2\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{H}^{+}\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial } \\ {\left[\mathrm{CH}_3 \mathrm{COCH}_3\right]} \\ \left(\mathrm{mol} \mathrm{L}^{-1}\right) \end{array} & \begin{array}{c} \text { Initial rate of decrease of } \mathrm{I}_2 \\ \left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}^{-1}\right) \end{array} \\ \hline 1 & 0.01 & 0.1 & 0.1 & 0.096 \\ 2 & 0.01 & 0.2 & 0.1 & 0.192 \\ 3 & 0.02 & 0.2 & 0.1 & 0.192 \\ 4 & 0.01 & 0.2 & 0.2 & 0.384 \\ \hline \end{array}$ The order with respect to $\mathrm{I}_2, \mathrm{H}^{+}$, acetone and total order of the reaction respectively are:
  1. $0,2,1,3$
  2. $1,0,1,2$
  3. $0,1,1,2$
  4. $1,1,0,2$

Solution

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Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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