The increasing order of oxidation number of sulphur in the given compounds is

The increasing order of oxidation number of sulphur in the given compounds is
  1. $\mathrm{S}_{8} < \mathrm{S}_{2} \mathrm{O}_{3}^{2-} < \mathrm{S}_{4} \mathrm{O}_{6}^{2-} < \mathrm{S}_{2} \mathrm{O}_{8}^{2-}$
  2. $\mathrm{S}_{8} < \mathrm{S}_{2} \mathrm{O}_{3}^{2-} < \mathrm{S}_{4} \mathrm{O}_{8}^{2-} < \mathrm{S}_{4} \mathrm{O}_{6}^{2-}$
  3. $\mathrm{S}_{8} < \mathrm{S}_{2} \mathrm{O}_{8}^{2-} < \mathrm{S}_{2} \mathrm{O}_{3}^{2-} < \mathrm{S}_{4} \mathrm{O}_{6}^{2-}$
  4. $\mathrm{S}_{8} < \mathrm{S}_{2} \mathrm{O}_{8}^{2-} < \mathrm{S}_{4} \mathrm{O}_{6}^{2-} < \mathrm{S}_{2} \mathrm{O}_{3}^{2-}$

Solution

The oxidation number of $\mathrm{S}$ in the given compounds are $0\left(ight.$ for $\left.\mathrm{S}_{8}ight),+2\left(ight.$ for $\left.\mathrm{S}_{2} \mathrm{O}_{3}^{2-}ight),+2.5\left(ight.$ for $\left.\mathrm{S}_{4} \mathrm{O}_{6}^{2-}ight)$ and $+6$
(for $\mathrm{S}_{2} \mathrm{O}_{8}^{2-}$ whose structure is

Asked in: JEE-TOPICTESTS-CHEMISTRY

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