The increasing order of $\mathrm{PH}^{\mathrm{H}}$ of $0.1 \mathrm{M}$ solution of the following compounds is

The increasing order of $\mathrm{PH}^{\mathrm{H}}$ of $0.1 \mathrm{M}$ solution of the following compounds is
  1. $\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCN}<\mathrm{NH}_4 \mathrm{NO}_3$
  2. $\mathrm{NH}_4 \mathrm{ON}_3<\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCH}$
  3. $\mathrm{BaCN}<\mathrm{HCl} \mathrm{NH}{ }_4 \mathrm{NO}_3<\mathrm{HCl}$
  4. $\mathrm{HCl}<\mathrm{NH}_4 \mathrm{NO}_3<\mathrm{NaCl}<\mathrm{NaCN}$

Solution

$\mathrm{HCl}$ (SA), $\mathrm{NH}_4 \mathrm{NO}_3$ (SAWB), $\mathrm{NaCl}(\mathrm{SASB}) \mathrm{NaCN}$ (WASB)

Asked in: MHT CET 2022 (07 Aug Shift 2)

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