The increasing order of nucleophilicity of the following nucleophiles is;

The increasing order of nucleophilicity of the following nucleophiles is;

1. $\left(\mathrm{i}\right)<\left(\mathrm{i}\mathrm{v}\right)<\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)<\left(\mathrm{i}\mathrm{i}\right)$
2. $\left(\mathrm{i}\mathrm{i}\right)<\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)<\mathrm{ }\left(\mathrm{i}\mathrm{v}\right)<\left(\mathrm{i}\right)$
3. $\left(\mathrm{i}\mathrm{v}\right)<\left(\mathrm{i}\right)<\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)<\left(\mathrm{i}\mathrm{i}\right)$
4. $\left(\mathrm{i}\mathrm{i}\right)<\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)<\left(\mathrm{i}\right)<\left(\mathrm{i}\mathrm{v}\right)$

Solution

Anions are more nucleophilic than neutral. So, ${\mathrm{H}}_2\mathrm{O}$ is least nucleophilic.
nucleophilicity$\propto {\mathrm{e}}^{-}\mathrm{ }$ density



Greater the delocalization of charge, lesser will be nucleophilicity.

$\mathrm{O}{\mathrm{H}}^{-}>\mathrm{C}{\mathrm{H}}_3\mathrm{C}\mathrm{O}{\mathrm{O}}^{-}>\mathrm{C}{\mathrm{H}}_3\mathrm{S}{\mathrm{O}}_3^{-}>{\mathrm{H}}_2\mathrm{O}$

Asked in: JEE Main 2019 (10 Apr Shift 2)

Practice more General Organic Chemistry questions on Aicharya