The increasing order of crystal field splitting strength of the given ligands is

The increasing order of crystal field splitting strength of the given ligands is

$N H_{3} < C l^{-} < C N^{-} < F^{-} < C O < H_{2} O$
$F^{-} < C l^{-} < N H_{3} < C N^{-} < H_{2} O < C O$
$C l^{-} < F^{-} < H_{2} O < N H_{3} < C N^{-} < C O$
$C O < C N^{-} < N H_{3} < H_{2} O < F^{-} < C l^{-}$

Solution

In general, the ligands can be arranged in a series in the order of increasing field strength as

I^{-} < B r^{-} < S C N^{-} < C l^{-} < S^{2 -} < F^{-} < O H^{-} < C_{2} O_{4}^{2 -} < H_{2} O < N C S^{-} < E D T A^{4 -} < N H_{3} < e n < N O_{2}^{-} < C N^{-} < C O

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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