The incentre of the triangle with vertices $A(1, \sqrt{3}), B(0,0)$ and $C(2,0)$ is
- $\left(1, \frac{\sqrt{3}}{2}\right)$
- $\left(\frac{2}{3}, \frac{1}{\sqrt{3}}\right)$
- $\left(\frac{2}{3}, \frac{\sqrt{3}}{2}\right)$
- $\left(1, \frac{1}{\sqrt{3}}\right)$
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 2)