The in-centre of the triangle formed by the lines $x=0, y=0$ and $3 x+4 y=12$ is

The in-centre of the triangle formed by the lines $x=0, y=0$ and $3 x+4 y=12$ is
  1. $\left(\frac{1}{2}, \frac{1}{2}\right)$
  2. $(1,1)$
  3. $\left(1, \frac{1}{2}\right)$
  4. $\left(\frac{1}{2}, 1\right)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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