The identical spheres each of mass 2 M are placed at the corners of a right angled triangle with mutually…

The identical spheres each of mass 2M are placed at the corners of a right angled triangle with mutually perpendicular sides equal to 4 m each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is 42x, where the value of x is ________.

Solution

Position vector rCOM=m1r1+m2r2+m3r3 m1+m2+m3

rCOM =2M×0+2M×4i^+2M×4j^6M

r=43i^+43j^

|r|=432+432=423

Therefore, x=3.

Asked in: JEE Main 2024 (01 Feb Shift 1)

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