The hydrocarbon $(X)$ with molar mass $80 \mathrm{~g} \mathrm{~mol}^{-1}$ and $90 \%$ carbon has $\ldots\ldots$ degree of unsaturation.

Question

Aicharya · Accepted Answer

$	herefore$ Empirical formula is $\mathrm{C}_3 \mathrm{H}_4$ Molecular mass $=80 \mathrm{~g} \mathrm{~mol}^{-1}$. Molecular formula $=\left(\mathrm{C}_3 \mathrm{H}_4ight)_{\mathrm{n}}$ $\mathrm{n}=\frac{	ext { Molecular mass }}{\mathrm{EF} 	ext { mass }}=\frac{80}{40}=2$ $	herefore$ Molecular formula is $\mathrm{C}_6 \mathrm{H}_8$ Degree of unsaturation $=\frac{2 	imes 6+2-8}{2}=3$

The hydrocarbon $(X)$ with molar mass $80 \mathrm{~g} \mathrm{~mol}^{-1}$ and $90 \%$ carbon has…

Solution