The hybridization of P exhibited in PF 5 is sp x d y . The value of y is

The hybridization of P exhibited in PF5 is spxdy. The value of y is

Solution

The hybridization is sp3d hybridization and phosphorous atom forms five sp3d hybrid orbitals. Five hybrid orbitals will be used to form bonds with five fluorine atoms. There are 5 sigma bonds in this compound.

PF5⇒sp3d hybridisation

(5 sigma bonds, zero lone pair on central atom) Value of y=1

Asked in: JEE Main 2022 (28 Jun Shift 1)

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