The hybridization of iodine orbitals in the compound $\mathrm{IF}_{7}$ is

1. $\mathrm{sp}^{3} \mathrm{~d}$
2. $\mathrm{sp}^{3} \mathrm{~d}^{2}$
3. $\mathrm{sp}^{2} \mathrm{~d}^{3}$
4. $\mathrm{sp}^{3} \mathrm{~d}^{3}$

Solution

$\mathrm{sp}^{3} \mathrm{~d}^{3}$ hybridization is involved.
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Asked in: JEE-TOPICTESTS-CHEMISTRY

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