The hybridization of central atom of $\mathrm{ClF}_3, \mathrm{NH}_3, \mathrm{SO}_3$ are respectively
- $\mathrm{sp}^2, \mathrm{sp}^2, \mathrm{sp}^2$
- $\mathrm{sp}^3 \mathrm{~d}, \mathrm{sp}^3, \mathrm{sp}^2$
- $\mathrm{sp}^2, \mathrm{sp}^3, \mathrm{sp}^3 \mathrm{~d}$
- $\mathrm{sp}^3 \mathrm{~d}, \mathrm{sp}^3, \mathrm{sp}^3$
Asked in: AP EAMCET 2023 (18 May Shift 2)
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