The hybridisations of $\mathrm{N}$-orbitals in $\mathrm{NO}_3^{-}, \mathrm{NO}_2^{-}$ and…
The hybridisations of $\mathrm{N}$-orbitals in $\mathrm{NO}_3^{-}, \mathrm{NO}_2^{-}$ and $\mathrm{NH}_4^{+}$respectively are
- $s p^2, s p^2, s p^3$
- $s p, s p^3, s p^2$
- $s p, s p^2, s p^3$
- $s p^2, s p, s p^3$
Solution
As we know,
$
\text { Hybridisation }=\frac{1}{2}[V+M-C+A]
$
$
\begin{aligned}
\mathrm{H}_{\mathrm{NO}_3^{-}} & =\frac{1}{2}[5+0-0+1] \\
& =3 \text { i.e. } s p^2 \\
\mathrm{H}_{\mathrm{NO}_2^{-}} & =\frac{1}{2}[5+0-0+1] \\
& =3 \text { i.e. } s p^2 \\
\mathrm{H}_{\mathrm{NH}_4^{+}} & =\frac{1}{2}[5+4-1+0] \\
& =4 \text { i.e. } s p^3
\end{aligned}
$
The hybridisation of $\mathrm{N}$ in $\mathrm{NO}_3^{-}, \mathrm{NO}_2^{-}$and $\mathrm{NH}_4^{+}$are $s p^2, s p^2$ and $s p^3$ respectively
Asked in: AP EAMCET 2021 (23 Aug Shift 1)
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