The hybridisation of Xe and the number of lone pairs of electrons on it in $\mathrm{XeF}_6$ are
The hybridisation of Xe and the number of lone pairs of electrons on it in $\mathrm{XeF}_6$ are
$s p^3 d^2, 1$
$s p^3 d^3, 2$
$s p^3 d^2, 2$
$s p^3 d^3, 1$
Solution
$\mathrm{XeF}_6$ has distorted octahedral structure in which all the six position are occupied by fluorine atoms and one lone pair is present at the centre of one of the triangular faces. It involves $s p^3 d^3$ hybridisation of xenon.
