The Henry's law constant $\left(\mathrm{K}_H\right)$ values of three gases $(\mathrm{A}, \mathrm{B},…

The Henry's law constant $\left(\mathrm{K}_H\right)$ values of three gases $(\mathrm{A}, \mathrm{B}, \mathrm{C})$ in water are $145,2 \times 10^{-5}$ and 35 kbar , respectively. The solubility of these gases in water follow the order:
  1. B $\gt$ C $\gt$ A
  2. A $\gt$ C $\gt$ B
  3. A $\gt$ B $\gt$ C
  4. B $\gt$ A $\gt$ C

Solution

Value of Henry's law constant $\propto \frac{1}{\text { Solubility of gas }}$ Higher the value of $\mathrm{K}_H$ at a given pressure, lower is the solubility of the gas in the liquid. $\mathrm{K}_H$ value of gases (given) : $\mathrm{A}\gt\mathrm{C}\gt\mathrm{B}$ $\therefore \quad$ Order of solubility of gases in water : $\mathrm{B}\gt\mathrm{C}\gt\mathrm{A}$

Asked in: NEET 2024

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