The helium and argon are put in the flask at the same room temperature ( 300 K). The ratio of average kinetic energies (per molecule) of helium and argon is :
(Give : Molar mass of helium $=4 \mathrm{~g} / \mathrm{mol}$, Molar mass of argon $=40 \mathrm{~g} / \mathrm{mol}$)

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Aicharya · Accepted Answer

$K. E=\frac{f}{2} K T$ For He and $\mathrm{Ar} \mathrm{f}=3$ $\frac{\mathrm{K} \cdot \mathrm{E}_{\mathrm{He}}}{\mathrm{~K} \cdot \mathrm{E}_{\mathrm{Ar}}}=\frac{1}{1}$

The helium and argon are put in the flask at the same room temperature ( 300 K). The ratio of average…

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