The halflife of a radioactive element is 20 min. The time interval between the stages of its $33 \%$ and $67…
- $40 \mathrm{~min}$
- $20 \mathrm{~min}$
- $30 \mathrm{~min}$
- $25 \mathrm{~min}$
Solution
$67 \% \frac{\text { Half }}{\text { change }} 33.5(\approx 33 \%)$
So time interval between the stages of its $33 \%$ and $67 \%$ decay is same as $t_{1 / 2}=20 \mathrm{~min} .$ ^
Asked in: JEE-TOPICTESTS-CHEMISTRY