The half-life of a radioactive sample is \(T\). The fraction of the initial mass of the sample that decays…
The half-life of a radioactive sample is \(T\). The fraction of the initial mass of the sample that decays in an interval \(T / 2\) is
- \(\frac{1}{\sqrt{2}}\)
- \(\sqrt{2}\)
- \(\frac{(\sqrt{2}-1)}{\sqrt{2}}\)
- \(\frac{(\sqrt{2}+1)}{\sqrt{2}}\)
Solution
Fraction remains after \(n\) half-lives is given as
\(\frac{N}{N_0}=\left(\frac{1}{2}\right)^n=\left(\frac{1}{2}\right)^{t / T} \quad\) [where, \(T\) is half-life]
\(\Rightarrow \quad \frac{N}{N_0}=\left(\frac{1}{2}\right)^{\frac{t}{T}}\)
Given, \(\quad t=\frac{T}{2}\)
\(\therefore \quad \frac{N}{N_0}=\left(\frac{1}{2}\right)^{\frac{T / 2}{T}}=\left(\frac{1}{2}\right)^{\frac{1}{2}}=\frac{1}{\sqrt{2}}\)
Asked in: AP EAMCET 2020 (21 Sep Shift 2)
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