The H amount of thermal energy is developed by a resistor in 10   s when a current of 4   A is…

The H amount of thermal energy is developed by a resistor in 10 s when a current of 4 A is passed through it. If the current is increased to 16 A, the thermal energy developed by the resistor in 10 s will be
  1. H
  2. 16H
  3. H4
  4. 4H

Solution

Heat energy developed in the resistor due to current is given by, H=i2Rt. Therefore 

Hi2 (for t= constant)

Now required ratio, HH'=4162

H'=16H

Asked in: JEE Main 2023 (31 Jan Shift 2)

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