The gyromagnetic ratio of an electron in a hydrogen atom, according to Bohr model is
The gyromagnetic ratio of an electron in a hydrogen atom, according to Bohr model is
decreases with the quantum number ' $n$ '
independent of which orbit it is in
negative
positive
Solution
$\begin{aligned}
& \text { Gyromagnetic ratio }=\frac{\text { Magnetic Moment }}{\text { Angular Momentum }} \\
& =\frac{\mathrm{iA}}{\mathrm{mvr}}=\frac{\left(\frac{\mathrm{e} \omega}{2 \pi}\right)\left(\pi \mathrm{r}^2\right)}{\mathrm{m}(\mathrm{r} \omega) \mathrm{r}}=\frac{\mathrm{e}}{2 \mathrm{~m}}
\end{aligned}$
It is independent of the orbit of the electron