The ground state energy of hydrogen atom is $-13 \cdot 6 \mathrm{eV}$. The kinetic and potential energy of…

The ground state energy of hydrogen atom is $-13 \cdot 6 \mathrm{eV}$. The kinetic and potential energy of the electron in the second excited state is respectively
  1. $+3 \cdot 02 \mathrm{eV},-1 \cdot 51 \mathrm{eV}$
  2. $1 \cdot 51 \mathrm{eV},-3 \cdot 02 \mathrm{eV}$
  3. $-1 \cdot 51 \mathrm{eV},+3 \cdot 02 \mathrm{eV}$
  4. $+3 \cdot 02 \mathrm{eV},+1 \cdot 51 \mathrm{eV}$

Solution

For second excited state $n=3$ Total energy in the third orbit $E_{3}=\frac{-13.6}{9} \mathrm{eV}=-1.51 \mathrm{eV}$ K.E. $=-$ T.E. $\quad=1.51 \mathrm{eV}$ P.E. $=2$.T.E. $=-3.02 \mathrm{eV}$ .

Asked in: MHT CET 2020 (19 Oct Shift 1)

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