The greatest positive integer which divides $(n+16)$ $(n+17)(n+18)(n+19)$, for all positive integers $n$, is
The greatest positive integer which divides $(n+16)$ $(n+17)(n+18)(n+19)$, for all positive integers $n$, is
$6$
$24$
$28$
$20$
Solution
Given, $(n+16)(n+17)(n+18)(n+19)$
As we can observe that these numbers are th product of four consecutive natural numbers.
This number gets divided by $4 !=24$.