The gravitational potential energy of a body on the surface of the earth is E. If the body is taken from the surface of the earth to a height equal to $150 \%$ of the radius of the earth, its gravitational potential energy is

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Aicharya · Accepted Answer

$\mathrm{E}=\frac{-\mathrm{GMm}}{\mathrm{R}}, \mathrm{h}=1.5 \mathrm{R}$ $\begin{aligned} & 	herefore \quad \mathrm{R}^{\prime}=(\mathrm{R}+\mathrm{h})=(\mathrm{R}+1.5 \mathrm{R})=2.5 \mathrm{R} \ & 	herefore \quad \mathrm{E}^{\prime}=-\frac{\mathrm{GMm}}{\mathrm{R}^{\prime}}=-\frac{\mathrm{GMm}}{2.5 \mathrm{R}}=\frac{1}{2.5}\left(-\frac{\mathrm{GMm}}{\mathrm{R}}ight) \ & 	herefore \mathrm{E}^{\prime}=\frac{\mathrm{E}}{2.5}=0.4 \mathrm{E}\end{aligned}$

The gravitational potential energy of a body on the surface of the earth is E. If the body is taken from the…

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