The graph which depicts the results of Rutherford gold foil experiment with α -particles is: θ :…

The graph which depicts the results of Rutherford gold foil experiment with α -particles is:
θ: Scattering angle
Y: Number of scattered α -particles detected
(Plots are schematic and not to scale)

Solution

Rutherford carried out an experiment in which he bombarded a thin sheet of gold foil with α-particles and then analysed the trajectory of these particles after they collided with the gold foil.

For a detector at a specific angle with respect to the incident beam, the number of particles per unit area striking the detector is given by the Rutherford formula,

Yθ=NinLZ2k2e44r2KE2sin4θ2

Here, Ni= Number of incident alpha particles,

n= Atoms per unit volume in target,

L= Thickness of target,

Z= Atomic number of target,

e= Electron charge,

k= Coulomb's constant,

r= Distance between target and detector,

KE= Kinetic energy of alpha particles,

θ= Scattering angle.

Therefore, Y1sin4θ2

Asked in: JEE Main 2020 (08 Jan Shift 1)

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