The graph of kinetic energy against the frequency $(\mathrm{V})$ of incident light is as shown in the figure…

The graph of kinetic energy against the frequency $(\mathrm{V})$ of incident light is as shown in the figure. The slope of the graph and intercept on $X$ axis respectively are
  1. Planck's constant, threshold frequency
  2. work function, maximum K.E
  3. maximum K.E, threshold frequency
  4. Planck's constant, work function

Solution

$\mathrm{KE}=\mathrm{h} v-\phi_{0}$ $y=m x-c$ $\therefore \mathrm{m}=\mathrm{h}, \mathrm{c}=\phi_{0}$ .

Asked in: MHT CET 2020 (16 Oct Shift 2)

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