The given potentiometer has its wire of resistance 10   Ω . When the sliding contact is in the…

The given potentiometer has its wire of resistance 10 Ω. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 Ω resistor is:

  1. 10 V
  2. 5 V
  3. 409 V
  4. 4011 V

Solution

20-V05+0-V05+20-V02=0

4+10=2 V05+V02

14=4 V0+5 V010

V0=1409Volt

Potential difference across 2 Ω resistor is 20-V0

That is 20-1409 V

Hence, answer is 409 Volt

Asked in: JEE Main 2021 (25 Jul Shift 2)

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