The given following circuit is equivalent to

Question

Aicharya · Accepted Answer

Let $\mathrm{p}$ : The switch $\mathrm{S}_1$ $\mathrm{q}$ : The switch $\mathrm{S}_2$ The symbolic form is $(p \wedge \sim q) \vee(\sim p \wedge q) \vee(\sim p \wedge \sim q)$ $\begin{aligned} & \equiv(p \wedge \sim q) \vee[\sim p \wedge(q \vee \sim q)] \ & 	ext {...[Distributive Law] } \ & \equiv(p \wedge \sim q) \vee[\sim p \wedge t] \ & 	ext {...[Complement Law] } \ & \equiv(p \wedge \sim q) \vee \sim p \ & 	ext {...[Identity Law] } \ & \equiv \sim p \vee(p \wedge \sim q) \ & 	ext { [Commutative Law] } \ & \equiv(\sim p \vee p) \wedge(\sim p \vee \sim q) \ & 	ext {.[Distributive Law] } \ & \equiv \mathrm{t} \wedge(\sim \mathrm{p} \vee \sim \mathrm{q}) \ & 	ext {.[Complement Law] } \ & \equiv \sim p \vee \sim q \ & 	ext {.[Identity Law] } \ & \end{aligned}$

The given following circuit is equivalent to

Solution