The given circuit is equivalent to
Solution
Method 2: $\begin{aligned} & Y=\overline{\bar{A}+\bar{B}} \\ & Y=\overline{\bar{A}} \cdot \overline{\bar{B}}=A B\end{aligned}$ AND gate
Asked in: NEET 2023 (Manipur)
Method 2: $\begin{aligned} & Y=\overline{\bar{A}+\bar{B}} \\ & Y=\overline{\bar{A}} \cdot \overline{\bar{B}}=A B\end{aligned}$ AND gate