The geometries of $\mathrm{XeF}_4$ and $\mathrm{XeOF}_4$ respectively are

1. pyramidal and distorted octahedral
2. square pyramidal and square pyramidal
3. square planar and square pyramidal
4. square planar and square planar

Solution

The hybridisation of $\mathrm{XeF}_4$ is $s p^3 d^2$. So, the geometry is square planar.
The hybridisation of $\mathrm{XeOF}_4$ is $s p^3 d^2$ and the geometry is square pyramidal with 5 bond pairs and 1 lone pair.

Asked in: AP EAMCET 2021 (23 Aug Shift 1)

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