The general solution of the differential equation $\frac{d x}{d t}=\frac{x \log x}{t}$ is
The general solution of the differential equation $\frac{d x}{d t}=\frac{x \log x}{t}$ is
- lot $x-x=c$
- $\mathrm{e}^{\mathrm{ct}}+\mathrm{x}=0$
- $\log \mathrm{t}=\mathrm{x}+\mathrm{c}$
- $\mathrm{e}^{\mathrm{ct}}=\mathrm{x}$
Solution
$\begin{aligned} & \frac{d x}{d t}=\frac{x \log x}{t} \\ & \therefore \int \frac{d x}{x \log x}=\int \frac{d t}{t} \\ & \therefore \log |\log x|=\log |t|+\log c \\ & \therefore \log x=t c \Rightarrow x=e^{t c}\end{aligned}$
Asked in: MHT CET 2021 (23 Sep Shift 2)
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