The general formula of the compound formed when a metal $(M)$ of group 1 reacts with non-metal $(X)$ of…
The general formula of the compound formed when a metal $(M)$ of group 1 reacts with non-metal $(X)$ of group 16 is
$M X_6$
$M_2 X_3$
$M X_2$
$M_2 X$
Solution
Group 1 elements $(M)$ have electronic configuration of outermost shell as $n s^1$ and the group 16 elements $(X)$ have electronic configuration of outermost shell as $n s^2 n p^4$, where ' $n$ ' is the principal quantum number of outermost shell. $M$ is strong reducing agent and can easily lose its 1 electron to acquire the stable electronic configuration of noble gas. The group 16 elements require 2 electrons to complete their octet, so each $X$ atom will bind with two $M$ atoms. Therefore, $M_2 X$ compound is formed.