The gauge pressure at a depth of $50 \mathrm{~m}$ in a sea is (Density of sea water is $1025 \mathrm{~kg}…
The gauge pressure at a depth of $50 \mathrm{~m}$ in a sea is (Density of sea water is $1025 \mathrm{~kg} \mathrm{~m}^{-3}$ and $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )
$1025 \mathrm{~Pa}$
$512500 \mathrm{~Pa}$
$20000 \mathrm{~Pa}$
$15000 \mathrm{~Pa}$
Solution
The gauge pressure at a depth of $50 \mathrm{~m}$,
$\begin{aligned}
& P=\rho g h \\
& =1025 \times 10 \times 50 \\
& =512500 \mathrm{~Pa}
\end{aligned}$