The fundamental frequency of open pipe is 'n'. If it is closed from one end then frequency of the $2^{\text…

The fundamental frequency of open pipe is 'n'. If it is closed from one end then frequency of the $2^{\text {nd }}$ harmonic of closed pipe is higher by $200 \mathrm{~Hz}$ than ${ }^{\prime} \mathrm{n}^{\prime}$. The value of 'n' is
  1. $800 \mathrm{~Hz}$
  2. $200 \mathrm{~Hz}$
  3. $100 \mathrm{~Hz}$
  4. $400 \mathrm{~Hz}$

Solution

$\mathrm{n}=\frac{\mathrm{v}}{2 \ell}$ $2^{\mathrm{nd}}$ harmonic $=1^{\mathrm{st}}$ overtone $=(2 \mathrm{p}+1) \mathrm{n}_{0}=3 \mathrm{n}_{0}$ $\frac{3 \mathrm{v}}{4 \ell}-\frac{\mathrm{v}}{2 \ell}=200$ $\frac{v}{2 \ell}\left(\frac{3}{2}-1\right)=200$ $\frac{v}{2 \ell}=400$ ^

Asked in: MHT CET 2020 (20 Oct Shift 2)

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