The fundamental frequency of an open pipe of length 1m, if the speed of sound in air is $340\text{ ms}^{-1}$…
The fundamental frequency of an open pipe of length 1m, if the speed of sound in air is $340\text{ ms}^{-1}$ is
- 340 Hz
- 170 Hz
- 680 Hz
- 85 Hz
Solution
For open pipe, $\nu = \frac{v}{2l}$
Given, $v = 340\text{ ms}^{-1}, l = 1\text{ m}$
$\therefore \nu = \frac{340}{2 \times 1} = 170\text{ Hz}$
Practice more Waves and Sound questions on Aicharya