The fundamental frequency of an open pipe is 100 Hz . If the bottom end of the pipe is closed and $\frac{1}{3} \mathrm{rd}$ of the pipe is filled with water, then the fundamental frequency of the pipe is

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Aicharya · Accepted Answer

For open organ pipe, $\gamma_0=\frac{v}{2 L}=100 \mathrm{~Hz}$ For closed organ pipe $\begin{aligned} & \frac{2 \mathrm{~L}}{3}=\frac{\lambda}{4} \\ & \therefore \quad \lambda=\frac{8 \mathrm{~L}}{3} \end{aligned}$ $\therefore$ Fundamental frequency $\gamma_0^1=\frac{\mathrm{v}}{\lambda}=\frac{\mathrm{v}}{8 \mathrm{~L}}=\frac{3 \mathrm{v}}{8 \mathrm{~L}}=\frac{3}{4}\left(\frac{\mathrm{v}}{2 \mathrm{~L}}\right)=\frac{3}{4} \times 100=75 \mathrm{~Hz}$

The fundamental frequency of an open pipe is 100 Hz . If the bottom end of the pipe is closed and…

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