The fundamental frequency of air column in pipe 'A' closed at one end is in unison with second overtone of…
The fundamental frequency of air column in pipe 'A' closed at one end is in unison with second overtone of an air column in pipe 'B' open at both ends. The ratio of length of air column in pipe 'A' to that of air column in pipe ' $\mathrm{B}$ ' is
$1: 6$
$3: 8$
$2: 3$
$3: 4$
Solution
Fundamental frequency of ta closed pipè, $\mathrm{n}_1=\frac{\mathrm{v}}{4 \mathrm{~L}_1}$
Frequency of the second overtone, $\mathrm{n}_2=\frac{3 \mathrm{v}}{2 \mathrm{~L}_2}$
Given $\mathrm{n}_1=\mathrm{n}_2$
$\Rightarrow \frac{\mathrm{v}}{4 \mathrm{~L}_1}=\frac{3 \mathrm{v}}{2 \mathrm{~L}_2}$
$\therefore \quad \frac{\mathrm{L}_1}{\mathrm{~L}_2}=\frac{1}{6}$